3.115 \(\int \frac {x \sinh ^{-1}(a x)}{\sqrt {1+a^2 x^2}} \, dx\)

Optimal. Leaf size=28 \[ \frac {\sqrt {a^2 x^2+1} \sinh ^{-1}(a x)}{a^2}-\frac {x}{a} \]

[Out]

-x/a+arcsinh(a*x)*(a^2*x^2+1)^(1/2)/a^2

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Rubi [A]  time = 0.05, antiderivative size = 28, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {5717, 8} \[ \frac {\sqrt {a^2 x^2+1} \sinh ^{-1}(a x)}{a^2}-\frac {x}{a} \]

Antiderivative was successfully verified.

[In]

Int[(x*ArcSinh[a*x])/Sqrt[1 + a^2*x^2],x]

[Out]

-(x/a) + (Sqrt[1 + a^2*x^2]*ArcSinh[a*x])/a^2

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 5717

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*(x_)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[((d + e*x^2)
^(p + 1)*(a + b*ArcSinh[c*x])^n)/(2*e*(p + 1)), x] - Dist[(b*n*d^IntPart[p]*(d + e*x^2)^FracPart[p])/(2*c*(p +
1)*(1 + c^2*x^2)^FracPart[p]), Int[(1 + c^2*x^2)^(p + 1/2)*(a + b*ArcSinh[c*x])^(n - 1), x], x] /; FreeQ[{a,
b, c, d, e, p}, x] && EqQ[e, c^2*d] && GtQ[n, 0] && NeQ[p, -1]

Rubi steps

\begin {align*} \int \frac {x \sinh ^{-1}(a x)}{\sqrt {1+a^2 x^2}} \, dx &=\frac {\sqrt {1+a^2 x^2} \sinh ^{-1}(a x)}{a^2}-\frac {\int 1 \, dx}{a}\\ &=-\frac {x}{a}+\frac {\sqrt {1+a^2 x^2} \sinh ^{-1}(a x)}{a^2}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 28, normalized size = 1.00 \[ \frac {\sqrt {a^2 x^2+1} \sinh ^{-1}(a x)}{a^2}-\frac {x}{a} \]

Antiderivative was successfully verified.

[In]

Integrate[(x*ArcSinh[a*x])/Sqrt[1 + a^2*x^2],x]

[Out]

-(x/a) + (Sqrt[1 + a^2*x^2]*ArcSinh[a*x])/a^2

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fricas [A]  time = 0.54, size = 38, normalized size = 1.36 \[ -\frac {a x - \sqrt {a^{2} x^{2} + 1} \log \left (a x + \sqrt {a^{2} x^{2} + 1}\right )}{a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arcsinh(a*x)/(a^2*x^2+1)^(1/2),x, algorithm="fricas")

[Out]

-(a*x - sqrt(a^2*x^2 + 1)*log(a*x + sqrt(a^2*x^2 + 1)))/a^2

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giac [A]  time = 0.41, size = 38, normalized size = 1.36 \[ -\frac {x}{a} + \frac {\sqrt {a^{2} x^{2} + 1} \log \left (a x + \sqrt {a^{2} x^{2} + 1}\right )}{a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arcsinh(a*x)/(a^2*x^2+1)^(1/2),x, algorithm="giac")

[Out]

-x/a + sqrt(a^2*x^2 + 1)*log(a*x + sqrt(a^2*x^2 + 1))/a^2

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maple [A]  time = 0.04, size = 47, normalized size = 1.68 \[ \frac {\arcsinh \left (a x \right ) x^{2} a^{2}+\arcsinh \left (a x \right )-\sqrt {a^{2} x^{2}+1}\, x a}{a^{2} \sqrt {a^{2} x^{2}+1}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*arcsinh(a*x)/(a^2*x^2+1)^(1/2),x)

[Out]

1/a^2/(a^2*x^2+1)^(1/2)*(arcsinh(a*x)*x^2*a^2+arcsinh(a*x)-(a^2*x^2+1)^(1/2)*x*a)

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maxima [A]  time = 0.36, size = 26, normalized size = 0.93 \[ -\frac {x}{a} + \frac {\sqrt {a^{2} x^{2} + 1} \operatorname {arsinh}\left (a x\right )}{a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arcsinh(a*x)/(a^2*x^2+1)^(1/2),x, algorithm="maxima")

[Out]

-x/a + sqrt(a^2*x^2 + 1)*arcsinh(a*x)/a^2

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mupad [F]  time = 0.00, size = -1, normalized size = -0.04 \[ \int \frac {x\,\mathrm {asinh}\left (a\,x\right )}{\sqrt {a^2\,x^2+1}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x*asinh(a*x))/(a^2*x^2 + 1)^(1/2),x)

[Out]

int((x*asinh(a*x))/(a^2*x^2 + 1)^(1/2), x)

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sympy [A]  time = 0.44, size = 24, normalized size = 0.86 \[ \begin {cases} - \frac {x}{a} + \frac {\sqrt {a^{2} x^{2} + 1} \operatorname {asinh}{\left (a x \right )}}{a^{2}} & \text {for}\: a \neq 0 \\0 & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*asinh(a*x)/(a**2*x**2+1)**(1/2),x)

[Out]

Piecewise((-x/a + sqrt(a**2*x**2 + 1)*asinh(a*x)/a**2, Ne(a, 0)), (0, True))

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